Hi,

If I don't have an entity instance but I do have the entity's type and the string name of one of its fields, how can I create the corresponding IEntityFeld2 instance?

Cheers,

Ian.

Ian wrote:

Hi,

If I don't have an entity instance but I do have the entity's type and the string name of one of its fields, how can I create the corresponding IEntityFeld2 instance?

Use: IEntityField2 field = EntityFieldsFactory.CreateEntityFieldsObject(entityType)[fieldname];

Otis wrote:

IEntityField2 field = EntityFieldsFactory.CreateEntityFieldsObject(entityType)[fieldname];

Is this new functionality? I see this now, but don't remember seeing it before (although I may never have looked ).

I have a few spots where I create all the fields, then reference the fieldindex by an integer value. Now I can just create a single field (or maybe I always could)?

psandler wrote:

Otis wrote:

IEntityField2 field = EntityFieldsFactory.CreateEntityFieldsObject(entityType)[fieldname];

Is this new functionality? I see this now, but don't remember seeing it before (although I may never have looked ).

this is here since day 1

I have a few spots where I create all the fields, then reference the fieldindex by an integer value. Now I can just create a single field (or maybe I always could)?

This always generates all the fields for an entity, and selects a single one from the list. What you do is what I do here too, I just use the name instead of the index.

You can create a single field of course, by using EntityFieldFactory.Create(fieldenum.fieldname), but you already knew that